Someone please help with y=2^x?
Someone really really sweet helped me earlier today, but I dont think they are online.
the table is linear because the equation for it is \(y=2x\)
if you have the same ordered pairs as from the table
so then yes the table matches the graph
and to find the 10th, just look at the y when x = 10
so wait this would be linear or exponential? I'm all confused again :/
okay wait the table when graphed is linear and then the equation I get using exponential regression, has to be - exponential?
Okay I found a website that does exponential regression using a table. & I think I have to do y=ab^x my numbers are a= 2.550657097 and b=1.259112119 are these right?
you don't need to do exponential regression for this because it's linear. The line of best fit is exactly \[y=2x\]
I think I just thought it was expo because that's what the whole lessons about but yeah I mean it looks linear, but I still have to use expo regression (or constant ratio) to get an equation for this table and my rate of changes.
oh wait did you fill out that table or did they give it to you?
no I had to fill it in.
they gave me the first two and i did the rest
ok so each round DOUBLES # of rounds | ppl receiving forward 1 2 2 4 3 8 4 16
That would make it exponential
oh dang really? I knew my table was wrong, but I didn't know exactly how.
okay well at least that is cleared up.
i'm going to redo this graph in google to see how it looks
ok. I think it should go smoothly from there
okay yeah it looks exponential now
ok
those rates of changes aren't going to be correct because the points changed
oh yeah sorry sorry I realized that as I posted them.
We did exponential earlier. Once you have the graph you can add the trendline
How did we get exponential? I remember just the equation being on the side there.
yeah you have to add the equation from the advanced options where you go to edit the chart
something like advanced edit I think
yeah that's it
okay so I have y=1e^(0.693x) how do I graph this over my original graph?
I think it graphs automatically
or I guess the line is just the same because I'm not seeing a new line just the one I had
yeah they'll be very close together for this one because you made up the points to match the function. y = e^(0.693x) is basically the same as y = 2^x
okay yeah when I did advanced edit and all that stuff, the dot graph I had just changed to the plots being connected with a line, so I guess that they overlay eachother?
yeah that sounds right
how do I figure that out? Something with the 10th round?
@peachpi
my connection is so bad rn I don't know if I'm seeing replies
your equation is y = 2^x 50000 = 2^x Solve for x
15?
yes
awesome! Again I appreciate your help so much. Can't thank you enough <3
you're welcome
Join our real-time social learning platform and learn together with your friends!