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Mathematics 17 Online
OpenStudy (anonymous):

help please gold medals and fan haft to finish tonight

OpenStudy (jhannybean):

no question posted here.

OpenStudy (anonymous):

What is the rate of change of the linear relationship modeled in the table? x y −2 5 −1 4 0 3 1 2 −2 −1 negative one over two 1

OpenStudy (anonymous):

@Jhannybean

Vocaloid (vocaloid):

hint: notice the pattern in the y-values

OpenStudy (anonymous):

@Vocaloid the ones missing im guessing

Vocaloid (vocaloid):

uh, that's not quite what I meant the y values change by a certain amount each time, can you tell me what the pattern is?

OpenStudy (anonymous):

5 −1 4 0 3 1 2

OpenStudy (anonymous):

x y −2 5 −1 4 0 3 1 2

Vocaloid (vocaloid):

again, that's not quite what I meant.... the y values change by a certain amount, what is this amount?

OpenStudy (anonymous):

i dont get it @Vocaloid

Vocaloid (vocaloid):

well, tell me this, do the y-values increase or decrease?

OpenStudy (anonymous):

increasing @Vocaloid

Vocaloid (vocaloid):

are you sure? look at how the y-values change, going down the table...

OpenStudy (anonymous):

oh yea sorry i went up @Vocaloid

Vocaloid (vocaloid):

so, do the y-values increase or decrease?

OpenStudy (anonymous):

decrease @Vocaloid

Vocaloid (vocaloid):

correct, the numbers are decreasing, so we know our rate of change must be negative now, how much does each y-value decrease by, compared to the previous value?

OpenStudy (anonymous):

1 @Vocaloid

Vocaloid (vocaloid):

right, so our rate of change must be -1

OpenStudy (anonymous):

thank you sm @Vocaloid i was stuck on that for a little minute

OpenStudy (anonymous):

can you help me with something else @Vocaloid

Vocaloid (vocaloid):

sure

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