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(n-4)!+(4-n)!+2n!/2
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\[\frac{ (n-4)!+(4-n)!+2n! }{ 2 }\]
hint: if n-4>0 then n>4, so (4-n)! is not defined, being 4-n<0 and vice versa if 4-n>0
going on that n can only have one value ( assuming we are only dealing with whole numbers)
if n cannot be <4 nor >4 then n = ?
n=4 then thank you for your help!!
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