Combination Problem
The starting 5 in a basketball team is to be picked, in order, from the 10 playes in the squad. In how many ways can this be done if Jamahl and Anfernee must be in the starting 5. Remember this is a permutation question.
so you need to choose 3 other players from the remaining 8 this can be done in \(\dbinom{8}{3}\) ways
after that, you can permute the \(5\) member team : " Jamahl, Anfernee and the other \(3\) players" in \(5!\) ways
so there are \(\dbinom{8}{3}*5!\) ways to make the team
What do you mean by permuting 5 people in 5 ways @ganeshie8?
"permute" refers to a rearrangement for example : \((b,a,c,d,e)\) is a permutation of \((a,b,c,d,e)\)
after choosing 5 member for the team, you need to rank them in order right ?
AHH, I see what you mean. Thank you!
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