Question

???

Answer 1

seems like you want to take a derivative to me

Answer 2

I think thats what they're asking, so I would derive that equation to get 8x

Answer 3

almost, y' = 8xx'

Answer 4

do you know what an implicit is?

Answer 5

or rather, just take the derivative of both sides with respect to time, not with respect to x

Answer 6

Implicit differentiation?

Answer 7

yes
\[y = 4x^2+1\]
\[\frac{d}{dt}y = \frac{d}{dt}4x^2+\frac{d}{dt}1\]
\[\frac{dy}{dt} = \frac{dx}{dt}8x+0\]

Answer 8

dx/dt has been defined for us as 2

Answer 9

So now I would plug in my values?

Answer 10

of course

Answer 11

So it is increasing at a rate of 16?

Answer 12

correct

Answer 13

the key is seeing that x' is not defined as dx/dx in this case, so we take a derivative implicitly with respect to time, and not to x

Answer 14

Okay ill remember that for next time, thank you so much for your help!!!!!!

Answer 15

good luck