Mathematics
10 Online
OpenStudy (anonymous):
I have another log question :o
Log3(x^2)=2log3(4) - 4log3(5)
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OpenStudy (irishboy123):
latexed
\(log_3(x^2)=2log_3(4) - 4log_3(5)\)
is that right?
OpenStudy (anonymous):
Yep, that's right!
OpenStudy (welshfella):
by the laws of logs
log3 x^2 = log3 4^2 - log3 4^5
log3 x^2 = log3 (4^2 / 4^5)
can you continue?
OpenStudy (anonymous):
How did you get 4^5? Isn't it 5^4?
OpenStudy (welshfella):
** ooops sorry
that is 5^4 not 4^5
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OpenStudy (anonymous):
I got to where you are, and I understand it, but now I'm unsure of how to continue from there :o
OpenStudy (welshfella):
this is easy now..
OpenStudy (anonymous):
:/ Still not sure of how to proceed, sorry.
OpenStudy (welshfella):
if a^x = a^y
what is the relation between x and y?
OpenStudy (anonymous):
They're equal to each other, right?
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OpenStudy (welshfella):
yes
OpenStudy (anonymous):
x^2 = 16/625?
OpenStudy (welshfella):
yes
OpenStudy (anonymous):
so the final answer is x=4/25, right? Just want to make sure.
OpenStudy (welshfella):
right - what about -4/25?
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OpenStudy (welshfella):
catch question..
OpenStudy (anonymous):
Since it's log, you can't have a negative answer..
OpenStudy (anonymous):
...right?
OpenStudy (irishboy123):
why not put \(-\frac{4}{25}\) into the original equation....?
see if it works
you cruel man, @welshfella !!
OpenStudy (welshfella):
i know!!