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We say that a solution n of a congruence is unique modulo c if any solution n' of it is congruent to n modulo c. Can you give me an example?
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\(3x\equiv1(\text{mod }11)\) in \(\mathbb{Z}_{11}\)
only solution is \(4\), but if we change to \(\mathbb{Z}\) there are infinite solutions.
all solutions are x = 4 + 11k, right?
in \(\mathbb{Z}\)?
\(3(4+11k)-1=12+33k-1=11+33k=11(3k+1)\) yep
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