How do you find all the solutions for 'sin(x/2 - pi/4) = sqrt2/2'?
solutions imply an equation equations have an = sign your expression does not. is that a typo?
Yes, So sorry = sqrt2/2
Edited original.
do you know how to "undo" sin ?
Like using identities?
more like, do \(\sin^{-1} \) to both sides
\[ \sin^{-1} \left(\sin\left(\frac{x}{2} - \frac{\pi}{4}\right) \right)=\sin^{-1} \frac{\sqrt2}{2} \]
on the left side, the inverse sin of the sin undoes the sin we are left with \[ \frac{x}{2} - \frac{\pi}{4}=\sin^{-1} \frac{\sqrt2}{2} \]
on the right side it is asking for an angle what angle is it where sin of that angle = sqr(2)/2 we want it in radians and it is an angle people memorize (so you should too)
45 degrees or \[\pi\]/4
yes. but because the question asks for *all* solutions we should eyeball the graph for sin |dw:1440367395779:dw|
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