Question

Another factoring question

Answer 1

\(x^{3}y-4xy\) <---- this is the thing I have to factor

Answer 2

Well, what is common to both terms?

Answer 3

based from what phi told me in my previous question, I'm assuming that it would be acceptable to do this: \(xy(x^{2}-4)\)

Answer 4

and @anitasonia98 to answer your question, both terms have x and y in common

Answer 5

right ^_^ so once i have \(xy(x^{2}-4)\), that turns into xy(x-2)(x+2)

Answer 6

I believe that xy(x-2)(x+2) is my final form. Am I correct?

Answer 7

yes! Many thanks

Answer 8

That's right :)

Answer 9

this factoring business isn't as complicated as I recall :P

Answer 10

thats right :) ( ͡° ͜ʖ ͡°)