Choose the correct graph of the given system of equations. y − 2x = −1 x + 3y = 4
graph of two lines, one with a positive slope and one with a negative slope, that intersect at the point (negative 1, 1)
http://learn.flvs.net/webdav/assessment_images/educator_algebraI_v20/06_01_09b.gif
http://learn.flvs.net/webdav/assessment_images/educator_algebraI_v20/06_01_09b.gif
\(y-2x=-1\) \(x+3y=4\) Multiply the second one by \(2\) and we get \(y-2x=-1\) \(2x+6y=8\) now add them together \(7y=7\) so that \(y=1\) and now we find \(x\). \(x+3(1)=4\implies x=1\)
\((-1,1)\) is not their intersection. Make sense?
give me a moment please
no rush m8
so its either the second or third one
at the intersection the (x, y) given (-1, 1) satisfies both equations
\(1-2(-1)\ne -1\)
\((-1,1)\) Does NOT satisfy either equation @triciaal
graph of two lines, one with a positive slope and one with a negative slope, that intersect at the point (negative 1, 1) I misunderstood then so is the question incomplete?
Choose the correct graph of the given system of equations. y − 2x = −1 x + 3y = 4
I think those are his answers :)
i chose http://learn.flvs.net/webdav/assessment_images/educator_algebraI_v20/06_01_09b.gif
is it correct
@GiulianaRestrepo we can't see your choices. the solution is the graph where the (x, y) satisfies both equation
http://learn.flvs.net/webdav/assessment_images/educator_algebraI_v20/06_01_09b.gif
@triciaal
sketch each graph on the same grid and find the point where they meet
the first equation y = 2x -1 hint slope 2 and point (0, -1) is on that line the 2nd eqn 3y = -x + 4 slope negative and when y = 0 x = 4 so (4, 0) is on that line can you sketch each line and find (x, y) where they meet?
i already solved it thanks !
ok close the question.
Join our real-time social learning platform and learn together with your friends!