A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make at least $362 per day from bike and skate rentals combined. If they rent twice as many bikes as they do pairs of skates, what is the least number of pairs of skates they need to rent each day to make their minimum?

It needs to be in inequality form and I don't understand how to put it in that form for this problem.

Question

A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make at least $362 per day from bike and skate rentals combined. If they rent twice as many bikes as they do pairs of skates, what is the least number of pairs of skates they need to rent each day to make their minimum? 

It needs to be in inequality form and I don't understand how to put it in that form for this problem.

anonymous · Answer

Let x be the amount of bikes and y be the amount of skates. 
So then they make 21x from bikes and 20y from skates

anonymous · Answer

The total amount they make has to be AT LEAST ( ≥ ) $362. So,
$$21x+20y \ge 362$$

anonymous · Answer

twice as many bikes as pairs of skates mean
$$x=2y$$

Substitute back into the inequality to get

$$21(2y)+20y \ge 362$$

Solve for y

anonymous · Answer

Thank you! I got it figured out! :)

anonymous · Answer

you're welcome