seven apples and one orange cost 98 cents. two apples and three oranges cost 66 cents. find the cost of one apple and one orange

Question

anonymous · Answer

i bet you are supposed to solve $$7x+y=98\
2x+3y=66$$ where $x$ is the number of apples and $y$ is the number of oranges

anonymous · Answer

what next ?

zzr0ck3r · Answer

I would suggest either

1) multiplying the first equation by $-3$ and then adding the two equations.

2) Solve the first equation for $y$ and plug that into the second equation.

radar · Answer

Actually x is the cost of one apple and y is the cost of 1 orange.

radar · Answer

I would use substitution to solve.  Take the first equation 7x + y = 98 and express y in terms of x getting:  y = -7x + 98
Did you follow that with understanding?

radar · Answer

It appears that you went off line so I would assume you can take it from here.

radar · Answer

It is now simply a matter to substitute for y in the second equation and solve for x, then nail y.