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Mathematics 20 Online
OpenStudy (anonymous):

Alex drew a circle with right triangle PRQ inscribed in it, as shown below: The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center and angle R is a right angle. Arc QR measures 80 degrees. If the measure of arc QR is 80°, what is the measure of angle PQR? 50° 40° 80° 70°

OpenStudy (anonymous):

OpenStudy (arindameducationusc):

are you there?

OpenStudy (anonymous):

yeah

OpenStudy (arindameducationusc):

see if Qr=80 then, QPR=80/2

OpenStudy (arindameducationusc):

angle subtending arc= arc/2 (formula)

OpenStudy (anonymous):

oh alright

OpenStudy (anonymous):

so PQR=40

OpenStudy (arindameducationusc):

now, using angles of triangles. total angles (when added) =180 what we have here is 90+40+x=180

OpenStudy (arindameducationusc):

no its not 40

OpenStudy (arindameducationusc):

90+40(which we took out+x(which we have to find)=180 now solve for x, what do you get?

OpenStudy (anonymous):

50

OpenStudy (arindameducationusc):

Good! Thatz your answer

OpenStudy (anonymous):

ok thank you :)

OpenStudy (arindameducationusc):

No problem,

OpenStudy (anonymous):

can you help me with one more?

OpenStudy (anonymous):

Which of the following is a step in constructing a circle inscribed in a triangle? Use a compass to locate the intersection of the midpoint of each side. Use the perpendicular bisectors to find the center of the circle. Use a compass to locate the intersection of the altitude of each side. Use the angle bisectors to find the center of the circle.

OpenStudy (arindameducationusc):

I will try

OpenStudy (arindameducationusc):

hmmm.....

OpenStudy (anonymous):

is it the second one?

OpenStudy (arindameducationusc):

nopes. I dont think that. I think its D, but I am not sure.

OpenStudy (anonymous):

ok, i'll just google it to be sure lol

OpenStudy (arindameducationusc):

okay....

OpenStudy (arindameducationusc):

If you liked my response, dont forget to medal @ItzYaBoiGio

OpenStudy (anonymous):

alright

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