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Mathematics 21 Online
OpenStudy (trwatkins1):

Which values satisfy the inequality? |y| > 6 Choose all answers that are correct. A. y = –7 B. y = –1 C. y = 3 D. y = 9

OpenStudy (trwatkins1):

@SolomonZelman

OpenStudy (e.mccormick):

Well, yo can plug them in and try, but in general, whenever you see an absolute value inequality it means that the number will be constriend between two poiunts or NOT between those two points.

OpenStudy (mathstudent55):

To solve an equation of the form \(|X| = k\) where X is an expression with a variable and k is a non-negative number, solve the compound equation X = k or X = -k

OpenStudy (e.mccormick):

|x| < k means x will be between k and -k. |x| > k means x will be outside k and -k.

OpenStudy (mathstudent55):

Your expression with a variable is simply y. Set y equal to the number. Then set y equal to the negative of the number. Separate the equations with the word "or". That is the solution.

OpenStudy (trwatkins1):

ok

OpenStudy (e.mccormick):

So, based on all that, do you see the answer(s)?

OpenStudy (trwatkins1):

???????????

OpenStudy (mathstudent55):

Sorry. I misread the problem as as equation, y = |6|. Follow @e.mccormick as to how to find the answer the question.

OpenStudy (trwatkins1):

what do you mean by |x| > k means x will be outside k and -k.

OpenStudy (e.mccormick):

Because it is an inequality, y will be above or below some value. However, because y is in an absolute value, it means it is like being above or below two values: |x| > k means: x > k AND x > -k So if k is say 3, the line graph would be: |dw:1440444499449:dw| So it is OUTSIDE the -3 to 3 range.

OpenStudy (anas.p):

|y|= y with a positive sign this means that |-7|=7 and |7|=7 get it? |-3|=3 and |3|=3. Now try.

OpenStudy (e.mccormick):

If I did |x|<3, it would be: |dw:1440444653222:dw| That is inside...

OpenStudy (e.mccormick):

Or between. That is what I meant by it is between the numbers or outside those numbers. The > or < tells you which.

OpenStudy (trwatkins1):

>:( i still dont understand

OpenStudy (e.mccormick):

OK. Well, lets do try and see. |y| > 6 y = –7 y = –1 y = 3 y = 9 If you put -7 in place of y, is that true? If yes, then that is a valid answer. If no, it is not. Then repeat with -1, 3, and 9.

OpenStudy (trwatkins1):

@e.mccormick 9?

OpenStudy (e.mccormick):

Yes, |9| > 6 is true. However, there is another.

OpenStudy (trwatkins1):

3?

OpenStudy (e.mccormick):

|3| > 6 3 > 6 Three is greater than six... no, that is false.

OpenStudy (trwatkins1):

oh yea

OpenStudy (e.mccormick):

Remember how the absolute value works.

OpenStudy (trwatkins1):

so 7

OpenStudy (e.mccormick):

Yes. |y| > 6 means values outside the range of -6 to 6 are true. So values more than 6 and les than -6 would satisfy that. -7 is less than -6, so it is true.

OpenStudy (e.mccormick):

IF it had been |y| < 6, it would have been the other two. But for |y| > 6 it is A and D.

OpenStudy (e.mccormick):

I hope that makes more sense now.

OpenStudy (trwatkins1):

@e.mccormick 100%

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