Question

Counting Problem

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{4 men and 3 women are to be seated in row so that } \hspace{.33em}\\~\\
& \normalsize \text{no two women sit together. } \hspace{.33em}\\~\\
& \normalsize \text{Find the number of ways in which they can be seated. } \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

ok so we lsit the ways to do this can you think of any

Answer 3

\(\large \color{black}{\begin{align}
& a.)\ 4!\times ^{5}P_{3} \hspace{.33em}\\~\\
& b.)\ 4!\times ^{5}C_{3} \hspace{.33em}\\~\\
& c.)\ 4!\times ^{4}P_{3} \hspace{.33em}\\~\\
& d.)\ 4!\times ^{4}C_{3} \hspace{.33em}\\~\\
\end{align}}\)

Answer 4

@mathmate

Answer 5

i have found a link can any one explan me http://www.meritnation.com/ask-answer/question/m-men-and-n-women-are-to-be-seated-in-a-row-so-that-no-two-w/permutations-and-combinations/5901983

Answer 6

Yes, it does help!

Answer 7

So we first seat the 4 men, so there are 4! ways of seating the gents.