Question

can someone help me pls

Answer 1

E bisects

Answer 2

sure I will try :)

Answer 3

ok wait ill finish the question

Answer 4

e bisects df with a line over it, de =2y and ef=8y-3 find de ef and df

Answer 5

since E bisects DF, DE is equal to EF, so
2y = 8y-3 solve for y 3=6y .5 = y
so both DE and EF = 1
DF = DE + EF = 2
or
if E bisects DF, that means DE = EF.

Therefore, 2y = 8y - 3
3 = 6y
y = 0.5

DE = 1
EF = 1
DF = 2

Answer 6

ok thanks

Answer 7

sure :)

Answer 8

any other question

Answer 9

yea. During a football game, a quarterback standing at the 9-yard line passes the ball to a receiver at the 24-yard line. The receiver then runs with the ball halfway to the 50-yard line. How many total yards (passing plus running) did the team gain on the play?

Answer 10

From the 9 yrd. line to the 24 yard line is 15 yards.
Then it says he ran the ball HALFWAY to the 50 yard line. So he didn't quite make it to the 50 yard line.

SO: 50-24 = 26.. so 26 yards is the total distance from the 24 yard line to the 50 yard line.

But.. he only ran half of it. So 26/2 = 13. So.. 15 + 13 = 28 yards total gained on the play.

Answer 11

thanks again

Answer 12

yeah is that it if not just tag me :)

Answer 13

ok