Mathematics
14 Online
OpenStudy (anonymous):
Given f(x) = x^ 2+3 and g(x) = x+5/x find (g o f)(4)
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OpenStudy (anonymous):
I got 14/19
OpenStudy (anonymous):
@undeadknight26
undeadknight26 (undeadknight26):
I hate thees
OpenStudy (anonymous):
I hate them as much as you do, and it's barely the second day of school, sheesh.
undeadknight26 (undeadknight26):
Sorry m8
@dumbcow @Koikkara @Lady.Liv1776 @LunyMoony @whpalmer4 @rishavraj @rvc
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OpenStudy (anonymous):
. . . xD
OpenStudy (lunymoony):
What does the 'o' mean in " (g o f)" first though?
OpenStudy (dumbcow):
i dont like the notation for these
(f o g) is same as f(g)
so (g o f)(4) = g(f(4))
rvc (rvc):
g of f
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OpenStudy (lunymoony):
Ok, thx
OpenStudy (dumbcow):
plug in 4 into "f", then plug that num into "g"
OpenStudy (anonymous):
f(4) = x^2+3 and g(4)?
OpenStudy (dumbcow):
no , finish f(4) first .... what do you get?
OpenStudy (anonymous):
Finish f(4)? How do I do that?
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OpenStudy (dumbcow):
\[f(x) = x^2 +3\]
\[f(4) = 4^2 + 3\]
--you substitute the "x" with "4"
OpenStudy (anonymous):
Oh I figured.
f(4)=4^2+3
g(4)(4)?
OpenStudy (anonymous):
Nevermind I don't know what I'm doing.
OpenStudy (anonymous):
Can someone just tell me if I'm right or not? xD
OpenStudy (dumbcow):
oh sorry, so whats 4^2 +3 ?
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OpenStudy (anonymous):
Oh I thought that was the final product. I don't know f(x)
OpenStudy (dumbcow):
you are over thinking it..... 4^2 +3 = what
OpenStudy (anonymous):
19?
OpenStudy (dumbcow):
very good.... now use this number for function g
---> g(19) = (x+5)/x = (19+5)/19 = ?
OpenStudy (anonymous):
1.26?
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OpenStudy (dumbcow):
yeah or just 24/19
\[g(f(4)) = g(19) = \frac{24}{19}\]
OpenStudy (anonymous):
Oh, thank you so much!
OpenStudy (dumbcow):
yw