Question

@dumbcow

Answer 1

do you know pythagorean thm ?

Answer 2

Yea, for the most part.

Answer 3

ok

Answer 4

So I tried subtracting 9^2 by 5^2 and got 56.. I'm not sure what I've done wrong...

Answer 5

no thats right ... 81-25 = 56

now you have to take sqrt to solve for x

\[x^2 = 56\]
\[x = \sqrt{56}\]

Answer 6

I got 7.5 and it's not an option...

Answer 7

right be careful, notice the answer choices leave as radical not decimal

also we want Area, so we are not done

\[Area = 5*x = 5 \sqrt{56}\]

Answer 8

can you simplify the radical by factoring out a perfect square

Answer 9

No. I have no clue what that even means o.o (I'm sorry I'm so horrible at this >.<)

Answer 10

thats ok
the goal is to get the number inside the radical(sqrt) as small as possible
the only way to get rid of sprt is by having a perfect square .... 4,9,16,25...

example:
\[\sqrt{9} = \sqrt{3^2} = 3\]
also you can split up a sqrt into smaller factors
example:
\[\sqrt{45} = \sqrt{9*5} = \sqrt{9} \sqrt{5} = 3 \sqrt{5}\]
notice once you break it into sqrt9 and sqrt5 , you can get rid of sqrt9 because it equals 3

Answer 11

so how do I do that with 56... I don't understand

Answer 12

split it up ... like 45 has factors 9 and 5
what are factors of 56 .... try dividing by 4,9,16,25 etc

Answer 13

1,2,4,7,8,14,28,56,

Answer 14

yes look for perfect squares.... the only one is 4

4 pairs with 14

\[\sqrt{56} = \sqrt{4*14} = \sqrt{4} \sqrt{14}\]

Answer 15

..so my answer would be 14?

Answer 16

no dont try to jump ahead and just match a number to one of the answer choices

we want AREA of rectangle with sides 5 and sqrt(56)

we factored 56 into 4 and 14
\[\sqrt{56} = \sqrt{4} \sqrt{14} = 2 \sqrt{14}\]

Last multiply the 2 sides of rectangle to get AREA
\[Area = 5 * \sqrt{56} = 5 * 2 \sqrt{14} = 10 \sqrt{14}\]

Answer 17

Oh, okay. I think I get it now. Thanks.

Answer 18

yw keep working on simplifying radicals

Answer 19

gotta go :)

Answer 20

Ok have a good day