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OpenStudy (anonymous):
@welshfella
OpenStudy (anonymous):
There are 1,300 students in the school. Based on the sample proportion, how many students in the school would be expected to play indoor games for at least four hours every week?
546
598
702
1,248
OpenStudy (welshfella):
i've no idea on this one
OpenStudy (michele_laino):
we need to know the sample proportion
OpenStudy (anonymous):
ok then
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OpenStudy (michele_laino):
it is a missing data
OpenStudy (anonymous):
ok
OpenStudy (michele_laino):
do you know what is the sample proportion?
OpenStudy (anonymous):
no
OpenStudy (michele_laino):
please check the complete text of your exercise
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OpenStudy (anonymous):
is it 1,300
OpenStudy (michele_laino):
1,330 is the total number of the students
OpenStudy (michele_laino):
1,300*
OpenStudy (anonymous):
umm.. 1300 x 7 ?
OpenStudy (michele_laino):
the sample proportion, is a positive number and less than 1
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OpenStudy (anonymous):
0
OpenStudy (michele_laino):
no, zero can not be, since your options are all different from zero
OpenStudy (anonymous):
so 1?
OpenStudy (michele_laino):
the sample proportion has to be a data of your problem
OpenStudy (anonymous):
oh sorry let me show you the whole problem :)
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OpenStudy (michele_laino):
ok!
OpenStudy (anonymous):
OpenStudy (michele_laino):
the requested sample proportion is:
\[\Large \frac{{42}}{{42 + 52 + 4 + 2}} = ...?\]
OpenStudy (michele_laino):
please continue
OpenStudy (anonymous):
is it 59
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ok! so the requested number, is:
\[\Large 1300 \cdot \frac{{21}}{{50}} = ...?\]
OpenStudy (anonymous):
546!
OpenStudy (michele_laino):
yes!
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OpenStudy (anonymous):
Ivy has 4 tiles with pictures of plants and 5 tiles with pictures of animals. Ivy keeps all the tiles on a mat with the pictures hidden and mixes them up. She then turns one tile face up and finds the picture of a plant on it. She removes this tile from the mat and turns over another tile without looking. What is the probability that the second tile that Ivy turns over has a plant on it?
37.5%
44.4%
60.0%
80.0%