Question

Probability question

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{India plays two matches each with New Zealand and South Africa.} \hspace{.33em}\\~\\
& \normalsize \text{ In any match , the probability of different outcomes for India} \hspace{.33em}\\~\\
& \normalsize \text{ is given below -} \hspace{.33em}\\~\\~\\~\\
& \begin{array}{|c|c|c|} \hline
\text{Outcome} & \text{Win} & \text{Loss} & \text{Draw} \\ \hline
\text{Probablity} & 0.5 & 0.45 & 0.05 \\ \hline
\text{Points} & 2 & 0 & 1 \\ \hline
\end{array}
& \hspace{.33em}\\~\\
& \normalsize \text{1.) What is the probablity Soth africa getting atleast 4 points .} \hspace{.33em}\\~\\
& \normalsize \text{ assume south africa and newzealand play 2 matches. } \hspace{.33em}\\~\\
& a.)\ 0.2025 \hspace{.33em}\\~\\
& b.)\ 0.0625 \hspace{.33em}\\~\\
& c.)\ 0.0425 \hspace{.33em}\\~\\
& d.)\ \normalsize \text{ can't ve determined} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

i hate googling lol

Answer 3

^ :)

Answer 4

i hate googling (for answers only )lol

Answer 5

you can do it directly or use the complement...

Answer 6

P(at least 4 points) = 1 - P(at most 3 points)

Answer 7

okay so

Answer 8

\(\large \color{black}{\begin{align}
& 1-P(0)P(1)P(2)P(3) \hspace{.33em}\\~\\
\end{align}}\)

i m worried how to calculate

Answer 9

P(at most 3 points) = P(0 points) + P(1 point) + P(2 points) = P(3 points)

Answer 10

oh the addition

Answer 11

south africa played a total of 4 matches

Answer 12

Hey but the question is about South Africa, not India. We have no information on the probabilities of South Africa vs. New Zealand matches

Answer 13

is it can't be determined

Answer 14

oh i see phpilot

Answer 15

is it d.) ?

Answer 16

i think it is d

Answer 17

they didnt tell us anything about newzeland vs southafrica probabilities

Answer 18

it is given d.) in book too