Question

Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . .
A. -2003

B. -2040

C. -2060

D. -2038

Answer 1

@Michele_Laino

Answer 2

i thought it was b

Answer 3

the first term is:
a1=-8, the constant is d=2
so the requested sum, is:
\[\Large {S_8} = {a_1}\frac{{1 - {q^8}}}{{1 - q}} = - 8 \cdot \frac{{1 - 256}}{{1 - 2}} = ...?\]

Answer 4

\[r=\frac{ -16 }{ -8 }=2\]

Answer 5

i got the answer thnx for the help doe

Answer 6

Find the probability. What is the probability that a card drawn from a deck of 52 cards is not a 10?

Answer 7

i need help with this one though

Answer 8

A. 12/13

B. 9/10

C. 1/13

D. 1/10
is my answers

Answer 9

\[\frac{ C_{1}^{48} }{ C _{1}^{52} }=\frac{ 48 }{ 52 }=?\]

Answer 10

im not sure

Answer 11

@Nnesha @dan815

Answer 12

@Mehek14

Answer 13

it would be 1/13 right

Answer 14

\[\frac{ 48 }{ 52 }=\frac{ 12 }{ 13 }\]