Question

What is the missing value?
https://static.k12.com/bank_packages/files/media/mathml_6a898366c833b4d7194aa8d29fc91e60db252b97_1.gif



A.
−10

B.
−2

C.
2

D.
10

Answer 1

@jim_thompson5910

Answer 2

hint:

\[\LARGE \frac{x^a}{x^b} = x^{a-b}\]

Answer 3

D 10?

Answer 4

\[\LARGE \frac{x^a}{x^b} = x^{a-b}\]
\[\LARGE \frac{3^{-6}}{3^{{}^\boxed{}}} = 3^{4}\]
\[\LARGE \frac{3^{-6}}{3^{x}} = 3^{4}\]
\[\LARGE 3^{-6-x} = 3^{4}\]
set the exponents equal to one another and solve for x

Answer 5

You lost me.

Answer 6

where at?

Answer 7

The last part

Answer 8

when I went from \[\LARGE \frac{3^{-6}}{3^{x}} = 3^{4}\]
to
\[\LARGE 3^{-6-x} = 3^{4}\] ???

Answer 9

Yes

Answer 10

I used that rule I wrote in the hint. When you divide expressions like x^3 over x^2, you subtract the exponents

Answer 11

Is it a? -10

Answer 12

solve -6 - x = 10 for x

Answer 13

sorry I meant -6 - x = 4

Answer 14

negative - a negative = a positive = -6 - (-2) = 4


Right?

Answer 15

-6 - (-2) = 4 is false

Answer 16

-6 - (-2) = -4 is true

so try again

Answer 17

@jim_thompson5910

Answer 18

yes -6 - (-10) = -6 + 10 = 4

Answer 19

OKAY THANKS

Answer 20

no problem