Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (theloshua):

Find the domain of the following functions

OpenStudy (theloshua):

\[f(x)=\frac{ \sqrt{x+2} }{ x-5 }\]

OpenStudy (theloshua):

\[g(x)=\frac{ x-3 }{ \sqrt{x-1}}\]

jimthompson5910 (jim_thompson5910):

how far did you get with any of these?

OpenStudy (theloshua):

not far at all

OpenStudy (theloshua):

like i need helpppp i haves so much work to do and so lil time, i dont wanna be up all nite...

jimthompson5910 (jim_thompson5910):

well first off, hopefully you see that x-5 in the denominator cannot be zero, so x-5 = 0 leads to x = 5 if x = 5, then the denominator x-5 is 0 that means x = 5 is NOT part of the domain

jimthompson5910 (jim_thompson5910):

agreed so far?

OpenStudy (theloshua):

yes

jimthompson5910 (jim_thompson5910):

in the numerator of f(x), we have a radical you cannot take the square root of a negative number, so x+2 cannot be negative x+2 is either 0 or positive solve \[\Large x+2 \ge 0\] for x. Tell me what you get

OpenStudy (theloshua):

x greater or equal to -2

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (theloshua):

oh wait, i already solved for this one. i need help with the second

jimthompson5910 (jim_thompson5910):

so x cannot be 5 AND x has to be greater than or equal to -2

jimthompson5910 (jim_thompson5910):

same idea with g(x) you cannot divide by 0 and you cannot take the square root of a negative number

jimthompson5910 (jim_thompson5910):

what makes the denominator of g(x) equal to 0 ?

OpenStudy (theloshua):

3 cant be an option

jimthompson5910 (jim_thompson5910):

why not?

OpenStudy (theloshua):

because the top

OpenStudy (theloshua):

you subtract -3

OpenStudy (theloshua):

i mean add

OpenStudy (theloshua):

right?

jimthompson5910 (jim_thompson5910):

you can have 0 in the numerator though

jimthompson5910 (jim_thompson5910):

what do you get when you solve sqrt(x-1) = 0 for x?

OpenStudy (theloshua):

1

jimthompson5910 (jim_thompson5910):

so if x = 1, then the whole denominator turns to 0 which is why x = 1 is NOT part of the domain

jimthompson5910 (jim_thompson5910):

also, you need to ensure that x-1 is never negative

OpenStudy (theloshua):

okay

OpenStudy (theloshua):

and the other part?

jimthompson5910 (jim_thompson5910):

solve x-1 >= 0 for x to get what?

OpenStudy (theloshua):

1

jimthompson5910 (jim_thompson5910):

x = 1 ? or x <= 1 ? or x >= 1 ?

OpenStudy (theloshua):

x greater than 1

jimthompson5910 (jim_thompson5910):

greater than or equal to 1, yes

jimthompson5910 (jim_thompson5910):

oh wait, nvm the "or equal to" part

jimthompson5910 (jim_thompson5910):

x cannot equal 1 because it leads to a division by zero error

OpenStudy (theloshua):

okay

OpenStudy (theloshua):

so? explaiiiin im confused tell me how to solve

jimthompson5910 (jim_thompson5910):

you just said it: the domain is x > 1

jimthompson5910 (jim_thompson5910):

any number larger than 1 will work as an input if x = 1 or smaller, then you run into problems

OpenStudy (theloshua):

okay so the answer is x is not one and x is greater than 1?

jimthompson5910 (jim_thompson5910):

saying x > 1 implies that x is not equal to 1

jimthompson5910 (jim_thompson5910):

you don't need to say them both if you just say x > 1

OpenStudy (theloshua):

okay, so thats the answer tho

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (theloshua):

thnxxxx

jimthompson5910 (jim_thompson5910):

no problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!