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for f(x)=1/x^2-3 find for (2+h)
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hi!!
\[f(\spadesuit)=\frac{1}{\spadesuit^2-3}\] replace \(\spadesuit\) by \(2+h\)
@misty1212 i did I got 1/3h is that right?
idk i did't do it, but i am sure it is wrong
lets go slow
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first step is \[f(2+h)=\frac{1}{(2+h)^2-3}\]
second step is to square the \(2+h\) i.e. do \((2+h)(2+h)=4+4h+h^2\) giving \[\frac{1}{4+4h+h^2-3}\]
third step is the arithmetic, final answer is \[\frac{1}{4h+h^2+1}\]
ohh ok thank you I forgot to square it, can you help me with one more problem?
sure i will go to that post
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