Could you please explain mathematically what actually happens to the absolute value below

Question

marigirl · Answer

$$\ln \left| 2k^3-1 \right|=7.5$$

marigirl · Answer

Then I would go 
$$\left| 2k^3-1 \right|=e^(7.5)$$

marigirl · Answer

what will happen to the absolute function value now?

irishboy123 · Answer

try$$2k^3−1=\pm e^{7.5}$$

marigirl · Answer

My question was to solve for k which the value is + or - 9.67

how do we 'get rid' of an absolute value function, or how do we balance an absolute value function in an equation 

Since absolute value function only look at positive values, I am a little confused with your response @IrishBoy123

irishboy123 · Answer

let's say |x| = 3, then we can conclude that x = 3 OR x = -3

yes?

irishboy123 · Answer

ie, in that example i give,  we conclude $$x = \pm3$$

irishboy123 · Answer

so if $|x|=e^{7.5}$, you must consider  $x= \pm e^{7.5}$

irishboy123 · Answer

you should get two answers

$$\sqrt[3]{\frac{1 \pm e^{7.5}}{2}}$$

marigirl · Answer

oh yea it makes sense now,
I got k=9.67 and k=-9.66 

Thanks heaps! I really appreciate it

irishboy123 · Answer

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