Question

Use the distributive property to simplify the expression.
-6(1^2+3)-2(1^2-2)

Answer 1

HI!!

Answer 2

i am going to guess that there is a typo there
very rarely do you see \(1^2\)

Answer 3

\[-6(1^2+3)-2(1^2-2)\]is a number no need for the distributive law
could it be \[-6(x^2+3)-2(x^2-2)\]or something like that?

Answer 4

yeah it was like that but it wouldn't let me put it like that

Answer 5

with the \(x\)?

Answer 6

it doesn't say

Answer 7

it just say t^2

Answer 8

can you post a screen shot or an attachment?

Answer 9

ooh it is a \(t\) ok

Answer 10

\[-6(t^2+3)-2(t^2-2)\] right?

Answer 11

-6(t^2+3)-2(t^2-2)

Answer 12

ok multiply each term in the first parentheses by \(-6\)
what do you get?

Answer 13

idk

Answer 14

I think I calculated it wrong

Answer 15

\[-6(t^2+3)=-6\times t^2+-6\times 3\] is a start