Mathematics
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OpenStudy (shes.radical):
Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)] and select the correct answer below.
(a) m[n(x)]=4x-51
(b) m[n(x)]=4x-29
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OpenStudy (shes.radical):
(c) m[n(x)]=\[4x^2-51\]
(d) m[n(x)]= \[4x^2-29\]
Nnesha (nnesha):
\[\large\textrm {m[n(x)] is same as m(x-10)} \]
Nnesha (nnesha):
substitute x for n(x) function which is x-10 into m(x) function
OpenStudy (shes.radical):
...what??
Nnesha (nnesha):
:P
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Nnesha (nnesha):
n(x) =x-10
so they want u to replace x for x-10 into m(x) function
so\[\huge\rm m(\color{Red}{x-10})=4\color{reD}{x}-11\]
replace x with x-10
Nnesha (nnesha):
make sense ?
OpenStudy (shes.radical):
sorta..? ugh im so confused..now what?
OpenStudy (shes.radical):
so now its 4 (x-10) - 11 ?
OpenStudy (shes.radical):
its 4x-29! i get it now! lol, big help, thanks!
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Nnesha (nnesha):
how??
Nnesha (nnesha):
distribute parentheses by 4
4(x-10))=? ??
distribute parentheses by 4
OpenStudy (shes.radical):
4(x-10)-11 = 4x- 40- 11 = 4x - 29
Nnesha (nnesha):
-40-11= ?
Nnesha (nnesha):
both are negative so you would add
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OpenStudy (shes.radical):
oh..so then its 4x-51?
Nnesha (nnesha):
yes right
OpenStudy (shes.radical):
u rock..thank you!
Nnesha (nnesha):
my pleasure