Question

help me

Answer 1

@MadisonEmery

Answer 2

What do you think it is?

Answer 3

c

Answer 4

am i right

Answer 5

i am pretty sure c is correct but let me check 1 last time

Answer 6

what is the x at the bottom of the problem

Answer 7

idk lol

Answer 8

Note: as x approaches 1 the denominator approaches zero

Answer 9

you can use l'hopitals theorem to do this

find the derivative of the numerator and the denominator and plug in x = 1

Answer 10

are you familiar with this?

Answer 11

\[\frac{x^3+5 x^2+3 x-9}{x-1}=x^2+6 x+9 \]When x = 0, x^2+6 x+9=9

Answer 12

omg to many people helping lol this is consufing

Answer 13

c is not right

Answer 14

ok then what is

Answer 15

have you done l'hopitals rule in calculus?

Answer 16

i have not

Answer 17

oh well i can't think of any other way to do this. There probably is though...

Answer 18

man i just need to answer this question is there aother way to help with this

Answer 19

oh ok

if we factor the numerators we get
(x - 1)(x^2 + 6x + 9)
------------------
(x - 1)


so the x-1 cancels out to give x^2 + 6x + 9

Answer 20

now plug in x = 1 into x^2 + 6x + 9 and see what you get

Answer 21

i got 16

Answer 22

thats the answer

Answer 23

ok?