Question

Please help!!!!! MEDAL AND FAN!!!!!

Give the center coordinates (x,y) of the circle:

Answer 1

\[(x+3)^{2}+(y-4)^{2}=36\]

Answer 2

equation of a circle (x-h)^2 + (y-k)^2 = r^2
center (h,k) and radius r

Answer 3

Center = (-3,4)

This is because, as triciaal said, in the equation (x+3)2+(y−4)2=36, 3=h and 4=k

(H,K) are the coordinates of the center.

Answer 4

Oh ok

Answer 5

The definition of the circle is:
the loci of a point which is moving at constant distance from a fixed point.
So if the point is (h, k) and the constant distance is r,
by the distance formula:
\[\sqrt{(x-h)^2+(y-k)^2}=r\]
After squaring, equation of the circle:
\[(x-h)^2+(y-k)^2=r^2\]

Answer 6

When multiplied out, we obtain the
"general form" of the equation of a circle. Notice that in this form we can clearly see that the equation of a circle has both x2 and y2 terms and these terms have the same coefficient (usually 1).

Answer 7

Wait so which explanation should I go with because I a bit confused

Answer 8

@ikram002p

Answer 9

all are correct! different amount of details.

Answer 10

ok thx

Answer 11

yeah there all the same

Answer 12

But..... the first time I did this problem, I put -3,4 for my answer and got it wrong

Answer 13

ordered pairs should be in the form (h,k)
that is you should have (-3,4)

Answer 14

Maybe they already included the ( ). Don't know.

Answer 15

oh ok I will put it in parentheses

Answer 16

Could y'all help me on on more problem?

Answer 17

*one

Answer 18

Sure!

Answer 19

\[(x + 1)^{2} + (y - 6)^{2}= 2.25\]

Answer 20

Would the coords be (-1,6)?

Answer 21

yes the center would be (-1,6)

Answer 22

Absolutly right!

Answer 23

thx