Question

Probability question

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{A man and woman appear in an interview for 2 vacancies}\hspace{.33em}\\~\\
& \normalsize \text{of same post.The probablity of man's selection is }\ \dfrac{1}{4} \text{and that of } \hspace{.33em}\\~\\
& \normalsize \text{woman's selection is }\ \dfrac{1}{3}\ \text{What is the probablity that both } \hspace{.33em}\\~\\
& \normalsize \text{will be selected} \hspace{.33em}\\~\\
& a.)\ \dfrac{1}{12} \hspace{.33em}\\~\\
& b.)\ \dfrac{1}{3} \hspace{.33em}\\~\\
& c.)\ \dfrac{2}{5} \hspace{.33em}\\~\\
& d.)\ \dfrac{3}{7} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

Hint: they are independent events

Answer 3

man's selection doesn't depend on women's and vice versa

Answer 4

\(\large \color{black}{\begin{align}
& P(A\cap B)=P(A\cup B)-P(A)-P(B) \hspace{.33em}\\~\\
\end{align}}\)

Answer 5

i didn't understand

Answer 6

Do u mean this

\(\large \color{black}{\begin{align}
& P(A\cap B)=P(A)\times P(B) \hspace{.33em}\\~\\
\end{align}}\)

Answer 7

Yes they are independent events, so you simply multiply the probabilities