The production of water proceeds according to the following equation. 2H2(g) + O2(g) → 2H2O(g) Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water? a. Use a less-intense source of heat on the reactants. b. Maintain the same temperature of the reactants. c. Place the reactants in a smaller container. d. Reduce the concentration of the reactants.
Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.
Join our real-time social learning platform and learn together with your friends!