Question

Simplify 2 to the 5th over 3 squared all raised to the 4th power.

2 to the 20th over 3 to the 8th
2 to the 9th over 3 to the 8th
8 to the 5th over 12 to the 2nd
2 over 3 to the 2nd

Answer 1

Please help!!! ;)

Answer 2

@freckles @phi @perl

Answer 3

\(\Large(\frac{2^5}{3^2})^4\)

First, find 2^5 and 2^2

Answer 4

3^2 I mean

Answer 5

3 x 2?

Answer 6

@StudyGurl14 pls help is it multiplying??

Answer 7

@tkhunny

Answer 8

@perl @triciaal @ganeshie8 @Hero @phi

Answer 9

2 times 5 = 10 and 3 times 2 = 6

Answer 10

\(\left(a^{b}\right)^c = a^{b*c}\)

Do that.

Answer 11

how?

Answer 12

sorry but i dont know how @tkhunny

Answer 13

@StudyGurl14 pls explain

Answer 14

3^2 = 3 x 3

Answer 15

ohh

Answer 16

9

Answer 17

yeah.

Answer 18

Follow the pattern.

\(\left(\dfrac{2^{5}}{3^{2}}\right)^{4} = \dfrac{\left(2^{5}\right)^{4}}{\left(3^{2}\right)^{4}}\)

I'm pretty sure you can do that. Now the other part.

Answer 19

ok what about the other one?
is it 2 x 6?

Answer 20

studygirl

Answer 21

ugh tkhunny i dont! please its complicated

Answer 22

You should not ever see a '9' during the course of this problem.

Answer 23

what about 6?

Answer 24

is it 60/40?

Answer 25

like do u multiply 2 and 5 then 3 and 2 and then both by 4?

Answer 26

ok start over. first you multiply what?

Answer 27

@freckles

Answer 28

@IrishBoy123

Answer 29

is the final answer 0.66 to the 12th?

Answer 30

Use the rule.

\(\left(a^{b}\right)^{c} = a^{b*c}\) -- That's it. No great complication.

\(\left(2^{5}\right)^{4} = 2^{5*4} = 2^{20}\) -- No more. No less. Done.

You do the denominator.