Question

SIMPLE EQUATION, PLEASE EXPLAIN? IT'S ALGEBRA

Answer 1

1 1/2r - 2/3r = -3/2
5/6 = -3/2
6/5 x 5/6r = 6/5 x -3/2
r = -9/5 and simplified that would be r = -1 4/5

Answer 2

Did that help ? @HaperFink22

Answer 3

@kenialove I don't know. My friend was telling me otherwise :\ I'm confused

Answer 4

First convert the mixed number to an improper fraction
\[\Large 1 \frac{1}{2} = 1+\frac{1}{2}\]
\[\Large 1 \frac{1}{2} = 1*\color{red}{\frac{2}{2}}+\frac{1}{2}\]
\[\Large 1 \frac{1}{2} = \frac{2}{2}+\frac{1}{2}\]
\[\Large 1 \frac{1}{2} = \frac{2+1}{2}\]
\[\Large 1 \frac{1}{2} = \frac{3}{2}\]
Hopefully all this makes sense?

Answer 5

@jim_thompson5910 Could you please solve this expression specifically? It seems easy when I read your work but for some reason the problem above challenges me. :\

Answer 6

do you see how 1 & 1/2 is equal to 3/2 ?

Answer 7

@jim_thompson5910 Yes, but in this equation we're solving for r

Answer 8

So
\[\Large 1 \frac{1}{2}r - \frac{2}{3}r = -\frac{3}{2}\]
turns into
\[\Large \frac{3}{2}r - \frac{2}{3}r = -\frac{3}{2}\]

Answer 9

The LCD is 6. Multiply both sides by the LCD to clear out the fractions
\[\Large \frac{3}{2}r - \frac{2}{3}r = -\frac{3}{2}\]
\[\Large 6*\left(\frac{3}{2}r - \frac{2}{3}r\right) = 6*\left(-\frac{3}{2}\right)\]
\[\Large 6*\left(\frac{3}{2}r\right)+6*\left( - \frac{2}{3}r\right) = 6*\left(-\frac{3}{2}\right)\]
\[\Large 9r-4r = -9\]
Now solve for r

Answer 10

@jim_thompson5910 THANK YOU! That part with the LCD was what was confusing me so much. You subtract 9r - 4r which equals 5r.

5r = 9
r= 9/5

Answer 11

you lost a negative

Answer 12

it should be 5r = -9 and not 5r = 9

Answer 13

but you have the right idea: divide both sides by 5 to get r = -9/5

Answer 14

@jim_thompson5910 thanks for catching my mistake. I understand how this is done now :)

Answer 15

I'm glad it makes more sense now