Question

Algebra Help

Answer 1

Is the simplified form of \[2\sqrt{3}* 2\sqrt{6}\] rational?

Answer 2

Do you have an idea on what to do and are just unsure?

Answer 3

Answers:

A. Yes
B. No

Answer 4

No I don't really know

Answer 5

Ok, you can think about multiplying the numbers in front of the radical signs and the numbers under the radical signs separately.

Answer 6

ok so 2*2 is 4

Answer 7

Yes, and what is 3 * 6?

Answer 8

18

Answer 9

Ok so we have\[(2 \sqrt3 )(2\sqrt6) = 4\sqrt{18}\]

Answer 10

so is that rational ?

Answer 11

There is a 3^2 underneath the radical so you can pull that out\[4\sqrt{18} = 12\sqrt{2}\]

Answer 12

12 may be rational, but the sqrt 2 is not, so their product isn't rational either.

Answer 13

So its B

Answer 14

Yes, it isn't rational

Answer 15

so lets say though its like this \[2\sqrt{3}-2\sqrt{3}\] is that rational?

Answer 16

I think not?

Answer 17

Well is zero rational? What does it mean to be rational anyways? To be rational means that a number can be represented as some fraction with either the numerator or denominator being odd.

Answer 18

and you cant really have 0 in a fraction

Answer 19

Well we can right? I can put \[2\sqrt3 - 2\sqrt3 = 0 = \dfrac{0}{1}\]

Answer 20

oh ok I see that now so it would be rational

Answer 21

Yes

Answer 22

ok thanks allot

Answer 23

No problem, good luck in your studies.

Answer 24

thanks I need it xD