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Mathematics 19 Online
OpenStudy (anonymous):

Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle R? What is the measure of angle R? You must show all work and calculations to receive credit.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Hero @jim_thompson5910 @perl

jimthompson5910 (jim_thompson5910):

hint: with any inscribed quadrilateral in a circle, the opposite angles always add to 180 degrees that means angle R + angle P = 180 (3y+8) + (y) = 180

OpenStudy (anonymous):

Okay, i see that but i don't quite understand what to do cause im really confused on how to do this :/

jimthompson5910 (jim_thompson5910):

you just have to solve 3y+8+y = 180 for y

jimthompson5910 (jim_thompson5910):

3y+8+y = 180 4y+8 = 180 ... Combine like terms. 4y+8-8 = 180-8 ... Subtract 8 from both sides. 4y+0 = 172 4y = 172 ... ... ... y = ???

OpenStudy (anonymous):

43?

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

Yayy we got one(: now can you help me finish it ?

OpenStudy (anonymous):

@jim_thompson5910 or are we done with the problem ?

jimthompson5910 (jim_thompson5910):

now that you know the value of y, use it to compute angle R

OpenStudy (anonymous):

How do i do that .. i dont know how . Can you help me work through it ?

jimthompson5910 (jim_thompson5910):

what expression is shown for angle R

OpenStudy (anonymous):

the (3y +8) ?

jimthompson5910 (jim_thompson5910):

plug y = 43 into that and evaluate

OpenStudy (anonymous):

So (3 * 43 +8)?

jimthompson5910 (jim_thompson5910):

yes evaluate that

OpenStudy (anonymous):

54?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

that's too small

OpenStudy (anonymous):

then im confused , once i do the (3*43+8) .. im lost what to do

jimthompson5910 (jim_thompson5910):

how did you get 54 ?

OpenStudy (anonymous):

Oh i missed calculated i meant the answer would be 137?

jimthompson5910 (jim_thompson5910):

yes 137 is your answer

OpenStudy (anonymous):

Thank you!! So are we done with this question then ?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

Thank you soo much for your help!!

jimthompson5910 (jim_thompson5910):

you're welcome

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