Question

Hmmm...this is a dumb question, but to get rid of a fraction in an equation, do you multiply everything by the denominator of the fraction, or the reciprocal?

Answer 1

@jdoe0001 lol sorry for bothering you

Answer 2

no question is a dumb question

Answer 3

you would multiply `with the reciprocal` of the denominator

Answer 4

It is when you're in precal honors and can't remember basic math rules lol XD

Answer 5

thank you

Answer 6

\[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } }=\frac{ a }{ b } \times \frac{ d }{ c }\]

Answer 7

haha

Answer 8

im honers to

Answer 9

nice!

Answer 10

:3

Answer 11

there was a fellow the other day here
he said he knew physics, but never seen a logarithm :|

Answer 12

go figure

Answer 13

r u Muslim Nnesha

Answer 14

i am

Answer 15

So I have \(x^2-7x-\frac{3}{4}=0\), and to get rid of that fraction I'd multiply everything} by \(\frac{4}{3}\)?

Answer 16

ahh no!

Answer 17

wait...you said reciprocal of the denominator... so 1/4

Answer 18

yes, no, maybe so?

Answer 19

Oh, and @jdoe0001, I'm taking AP Physics right now XD I love it

Answer 20

yes right

Answer 21

That just creates more fractions D:

Answer 22

:3 x^2-7x-\frac{ 3 }{ 4} \times \frac{1}{4} \[x^2-7x-\frac{ 3 }{ 4} \times \frac{1}{4} \]
don't see any points to get more messy stuff :P

Answer 23

there are no dumb questions!!!!

Answer 24

i didn't noticed it's 1/4 not 4/3

Answer 25

thats what i sayed

Answer 26

I dunno...

Answer 27

ignore me plz :(

Answer 28

ummm... okay. I guess I'll just ask Mrs. Dunn tomorrow

Answer 29

no wait don't close !

Answer 30

nesha r u muslim i am

Answer 31

Please don't put spam on my question. >.<

Answer 32

\(\bf x^2-7x-\frac{3}{4}=0\implies 4\left( x^2-7x-\frac{3}{4} \right)=4(0)
\\ \quad \\
4x^2-21x-\cancel{4}\cdot \cfrac{3}{\cancel{4}}=0\implies 4x^2-21x-3=0\)

Answer 33

to get rid of a fraction in an equation, do you multiply everything by the denominator of the fraction, or the reciprocal?

you multiply everything by the lowest common denominator

Answer 34

hmmm rather \(\bf x^2-7x-\frac{3}{4}=0\implies 4\left( x^2-7x-\frac{3}{4} \right)=4(0)
\\ \quad \\
4x^2-28x-\cancel{4}\cdot \cfrac{3}{\cancel{4}}=0\implies 4x^2-28x-3=0\)

Answer 35

OKAY THANK YOU OMG.

Answer 36

remember the denominator of a whole number is 1

Answer 37

you are welcome

Answer 38

\(\color{#0cbb34}{\text{Originally Posted by}}\) @triciaal
remember the denominator of a whole number is 1
\(\color{#0cbb34}{\text{End of Quote}}\)
Yes, I know :D

Answer 39

fraction in the equation
i was doing totally different thin'!

Answer 40

srry about that

Answer 41

It's okay :) thanks guys