Question

I only have two left that I'm a little unclear on.

Answer 1

\(x+1-2\sqrt{x+4}=0\)

Answer 2

I have to solve that too

Answer 3

I know the 4 can come out of the radical

Answer 4

no

Answer 5

it's (x+4)

Answer 6

ohhhhhhhhhhhh

Answer 7

you can't separate it :(

Answer 8

yeah, when you wrote it that way I noticed.

Answer 9

so move all the terms to the right side instead sqrt{(x+4}

Answer 10

Why am I moving them?

Answer 11

you need to get sqrt{x+4} one one side and all other terms to opposite side so then you can take square both sides to cancel out the square root

Answer 12

OH THAT MAKES SENSE

Answer 13

i have \(\frac{1}{2}x+\frac{1}{2}=\sqrt{x+4}\)

Answer 14

right?

Answer 15

looks right

Answer 16

so \(x+4=\frac{1}{4}x+\frac{1}{4}\), right?

Answer 17

mhmm

Answer 18

so 0.75x=-3.75?

Answer 19

there is an easier way to do it

Answer 20

i hate fractions :P \[\huge\rm x+1-2\sqrt{x+4}=0\]
move the x+1 to the right side

Answer 21

\(-2\sqrt{x+4}=-x-1\)

Answer 22

looks good now move the -2 to the right side
remember we need just radical sign on one side

Answer 23

I already did that.

Answer 24

\(\color{Red}{-2}\sqrt{x+4}=-x-1\)
we just need radical at left side

Answer 25

oops

Answer 26

\(\sqrt{x+4}=\frac{1}{2}x+\frac{1}{2}\)

Answer 27

but, look:\(\color{#0cbb34}{\text{Originally Posted by}}\) @BloomLocke367
i have \(\frac{1}{2}x+\frac{1}{2}=\sqrt{x+4}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
I already did that

Answer 28

yes \[\sqrt{x+4}=\frac{ (x+1) }{ 2 }\]
which is same as 1/2x+1/2
but keep that to one fraction

Answer 29

when we finish with this question
please pnch on my forehead okay

Answer 30

hahaha okay XD

Answer 31

that's right but i don't how u got the negative sign

Answer 32

i'm sorry i'm tired actually
so i apologies

Answer 33

okay so how would you cancel out the square root ?

Answer 34

square both sides

Answer 35

yes right

Answer 36

so \(x+4=\frac{1}{4}x+\frac{1}{4}\)

Answer 37

which I also said already

Answer 38

\[\sqrt{x+4}= (\frac{x+1 }{ 2 })^2\]
that's how you should take square root at left side

Answer 39

so \(x+4=\frac{x^2+1}{4}\)

Answer 40

that's why i said it's better to combine them together
and no

Answer 41

*facepalm*

Answer 42

\[\huge\rm (\frac{ x+1 }{ 2 }) = \frac{ (x+1)^2 }{ 2^2 }\] both should be squared

Answer 43

sorry, everyone is talking around me and I just found out my boyfriend is in the ER... I'm a little distracted

Answer 44

mah don't `facepalm` :P

Answer 45

it's okay! :=)

Answer 46

oh right, that makes sense

Answer 47

x+2x+1 should be the numerator, right?

Answer 48

right now (x+1)^2 is same as (x+1)(x+1) you're an expert when it comes to foil method

Answer 49

typo

Answer 50

you sure it's x+2x +1 ?

Answer 51

X^2

Answer 52

UGH sorry

Answer 53

yes right :=) \[x+4=\frac{ x^2+2x+1 }{ 4 }\] now oslve for x

Answer 54

solve*

Answer 55

4x+16=x^2+2x+1?

Answer 56

to start with, that is

Answer 57

:=)

Answer 58

yes that's right

Answer 59

okay. so x^2-2x-15?

Answer 60

mhmm error!

Answer 61

what?

Answer 62

what error?

Answer 63

\[\color{ReD}{4x}+16=x^2\color{ReD}{+}2x+1\]

Answer 64

you would subtract 2x both sides right so
4x-2x = 2x not -2x :=)

Answer 65

\(\color{blue}{\text{Originally Posted by}}\) @BloomLocke367
okay. so x^2-2x-15?
\(\color{blue}{\text{End of Quote}}\)
so it's \[\huge\rm x^2+2x-15=0\]

Answer 66

no... 2x-4x=-2x

Answer 67

facedesk**

Answer 68

i moved all the terms to the left side
why i'm still looking on it
you're right god:(

Answer 69

hahaha, we both are having a tough time

Answer 70

meanwhile, I'm about to have a meltdown because I'm so worried...

Answer 71

anyhoo, I have (x-5)(x+3)=0

Answer 72

ah my fault

Answer 73

so my zeros are 5 and -3, right?

Answer 74

yes right solve for x
and what is the statement ? you have to find solutions right ?

Answer 75

yep

Answer 76

which I found

Answer 77

make sure you check your work
plugin 5 and -3 into the equation

Answer 78

there can be an extraneous solution!

Answer 79

yea, I know. I just have one more.. then I can go and quietly breakdown in my room. ;-;

Answer 80

i'm pretty you don't want to help anymore ahahhah

Answer 81

5 works. just checked

Answer 82

me*

Answer 83

yes right -3 is an extraneous

Answer 84

yep

Answer 85

alright good luck
btw what's ur next question ?

Answer 86

\(\sqrt x+x=1\)

Answer 87

is it okay if we do it on this thread ??

Answer 88

yea, I don't mind. I just wanna get this done

Answer 89

okay cool! that's the easy one
just like we did
move the x to the right side (bec we need the radical one side )

Answer 90

\(\sqrt x=-x+1\)

Answer 91

yes right take square both sides \[(\sqrt{x})^2= (-x+1)^2\]

Answer 92

(-x+1)(-x+1) =foil

Answer 93

x=x^2-2x+1

Answer 94

right solve for x :=)

Answer 95

I'm drawing a blank here, you know why. should I factor the right side, or move the x on the left to the right?

Answer 96

well should move the x to the right side
cuz there are like terms that we can combine

Answer 97

ok

Answer 98

if you factor right side that will not help you you still have to distribute factors with x