Question

If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the molarity of the barium hydroxide solution. Show all of the work used to solve this problem.

Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O

Answer 1

@taramgrant0543664 @Photon336

Answer 2

First step:
You can find the moles of nitric acid using n=cv
where n is the number of moles
c is the concentration (aka molarity) so 0.55M
v is volume and would need to be in litres not millilitres

Answer 3

ok im here

Answer 4

Second step:
Balance chemical equation
using the stoichiometric coefficients relate the HNO3 to the Ba(NO3)2
Using the ratio you can convert the moles of HNO3 to moles of Ba(NO3)2

Answer 5

Third Step:
After using the ratio you will have the moles of Ba(NO3)2
So you can use the formula c=n/v
c is the concentration that you are trying to find
n is the moles you found in the previous step
v is the volume in litres so the 15mL but converted

Answer 6

ok so the balanced equation is Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O

Answer 7

Yes it would be

Answer 8

So the ratio is 2 to 1
For every 2 moles of HNO3 there is 1 mole of Ba(NO3)2 produced

Answer 9

ok then what do i do

Answer 10

SO since the ratio is 2:1 the moles you found in step 1 you divide that by 2 to get the moles of Ba(NO3)2 and then you can carry on to step 3

Answer 11

C=N/V
0.55M=n/v

Answer 12

i thought ml was volume

Answer 13

mL is volume but since molarity is mol/L we have to convert the millilitres into litres
1L=1000mL

Answer 14

but it's not 1000 ml

Answer 15

That's the conversion
1mL=0.001L
48.3mL=? L

Answer 16

0.0483L

Answer 17

Yes using this and the 0.55M you can find n using the n=cv formula

Answer 18

0.0483*0.55=0.26565

Answer 19

Close I think you're missing a 0 in there

Answer 20

0.026565

Answer 21

remember to add both volumes (V1 + V2) to get your final volume

Answer 22

huh so 0.026565 isn't the answer?

Answer 23

Yes so now we look at the ratio it was 2:1 so to get the moles of Ba(NO3)2 you divide the moles you just got by 2 to get the moles of Ba(NO3)2

Answer 24

0.026565/2=0.0132825

Answer 25

Yes so that would be the moles of Ba(NO3)2
So now you put that into the formula c=n/v
and as @Photon336 had said you have to use the total volume so you have to add both together and convert that from millilitres to litres

Answer 26

so 48.3+15.0?

Answer 27

Yeo together that will be the final volume of the solution

Answer 28

48.3+15.0=63.3 ---> 0.0633

Answer 29

yep

Answer 30

so thats the final answer?

Answer 31

@lovingod786 they asked for concentration i think you need the number of moles too so it has to be moles/liter

Answer 32

Nope you have to put it into the formula first c=n/v

Answer 33

ok so c=0.26565/0.0633?

Answer 34

0.0132825/0.0633=c

Answer 35

0.21

Answer 36

yep that would be correct

Answer 37

m\[M _{1}V_{1} = m _{2}V_{2} \]

\[m_{2} = \frac{ M_{1}V{1} }{V_{2} }\]

\[m_{2}] = moles of Ba(OH)2 \[V_{2}] = final volume.

Answer 38

so thats the final answer then??

Answer 39

??

Answer 40

Yep

Answer 41

OK THX

Answer 42

You is a really good tutor or teacher or helper..you know whatever you clarify yourself as but you did a really good job!

Answer 43

Well do not did

Answer 44

Haha thanks! I try my best! I'm pretty bad at explaining things but this site has made me a lot better at explaining what I mean and @Photon336 is really good at explaining things too, probably one of the better people at explaining things in this section

Answer 45

Yeah @Photon336 is good too when I first got here they use to help me

Answer 46

thanks guys