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-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?
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Help Please.
Can you help me?
??
If -2i is a zero, then its conjugate 2i is also a zero. Multiply the factors \((x - 2i)(x+2i)\) Then divide your polynomial by the result using long division
x^2 -4i right?
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and I divide that into x^4 - 32x^2 - 144?
no. Should be \(x^2-4i^2\), which is \(x^2+4\). And then divide
ok
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