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Mathematics 22 Online
OpenStudy (anonymous):

-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?

OpenStudy (anonymous):

Help Please.

OpenStudy (anonymous):

Can you help me?

OpenStudy (anonymous):

??

OpenStudy (anonymous):

If -2i is a zero, then its conjugate 2i is also a zero. Multiply the factors \((x - 2i)(x+2i)\) Then divide your polynomial by the result using long division

OpenStudy (anonymous):

x^2 -4i right?

OpenStudy (anonymous):

and I divide that into x^4 - 32x^2 - 144?

OpenStudy (anonymous):

no. Should be \(x^2-4i^2\), which is \(x^2+4\). And then divide

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

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