Hello! Please help me work through this quadratic equation (it must be solved by completing the square): 2x^2 + 4x + 1 = 0

Question

anonymous · Answer

do you have to complete the square here?

sighn0more · Answer

Yes! So far I have moved the constant to the LHS and have factored out the 2. I don't know where to go from there.

anonymous · Answer

don't factor out the 2
you have an equation, divide by 2

anonymous · Answer

$$2x^2 + 4x + 1 = 0\2x^2 + 4x =-1\
x^2+2x=-\frac{1}{2}$$

anonymous · Answer

then complete mr square 
half of 2 is 1, and 1 squared is 1 go to 

$$(x+1)^2=-\frac{1}{2}+1$$

sighn0more · Answer

Ah, I see now. Okay, so from there I would have (x + 1)^2 = 1/2
and then x  = -1 + or -
 radical 1/2

anonymous · Answer

yes

sighn0more · Answer

Thank you! This helped a lot. Do you think that you can help me with one more problem? At least half way?