Question

Classical Mechanics Series; Hooke's Law

Answer 1

This is a simple tutoring on Hooke's law.

Answer 2

Hooke's law identifies the constant of a given string... or k.

k=F(applied)/Delta x

Where k denotes the force required to stretch or compress a spring per unit of length.

Answer 3

Usually K is measured in N/m.
Let's keep that as our rule of thumb in solving the following question.
The length of a stretched spring is 2m with an applied force of 16N.
To identify the k constant for the spring,

K=16N/2m=8N/m

Therefore the k constant for this spring is 8N/m

Answer 4

p.s Note that there is also a reference point in spring as well. You would measure the stretch or compression from the point of zero.

Answer 5

Alright, the next equation concerning Hooke's law is this,
E(energy stored in a compressed or stretched spring)=1/2(k)Delta(x)

Where,
E=potential stored
k=Hooke's constant
x=stretch, or compression of the spring.


With this formula alone you can calculate the energy stored in a spring, or potential energy from a spring being stretched or compressed.

Therefore, you look at the problem

Calculate the spring constant of a spring if a 15 kg mass is suspended from the spring and it stabilizes with a stretch of 12 cm.


First you need to look at the resulting force acting downwards to the gravity source, which is accounted for by (9.8m/s^2)(15kg)=147N

Next step is you must convert the 12cm to meters

12cm/100cm/m=0.12m

Then you would calculate the k constant

L=147N/0.12m=1225N/m

This tell us how much force is required to stretch or compress the spring by a meter.

Now using the formula E=1/2kx^2

E(potential energy stored in the spring)=1/2(1225N/m)(0.12cm)^2=8.82J

After accounting for sig figs of 2,

The energy stored in the spring is 8.8J.

Answer 6

Neat.....
Nice work robert!

Tell us about Kinetic energy also...
:)

Answer 7

good job! :)

Answer 8

I will be referring this tutorial in my tutorial, @Robert136

Answer 9

Great!

Answer 10

Wonderful :)