Question

Please help me!

Find x so that the distance between the points (6, -1) and (x, 9) is 12.

Answer 1

So far, this is what I have:\[12=\sqrt{x^2-12x+138}\]

Not sure what to do from here :/

Answer 2

still here ?

Answer 3

Yes I'm here!

Answer 4

\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
\[\Large 12 = \sqrt{\left(x-6\right)^2+\left(-1-9\right)^2}\]
\[\Large 12 = \sqrt{\left(x-6\right)^2+\left(-10\right)^2}\]
\[\Large 12 = \sqrt{x^2-12x+36+100}\]
\[\Large 12 = \sqrt{x^2-12x+136}\]
I'm not sure how you got 138. Did you mean 136??

Answer 5

Yeah, I meant 136

Answer 6

@ganeshie8 Please! I need a step by step guide.

Answer 7

square both sides, what do you get ?

Answer 8

\(12 = \sqrt{x^2-12x+136}\)

square both sides and get
\(144 = x^2-12x+136\)

rearranging a bit
\(x^2-12x-8=0\)

Answer 9

you may use quadratic formula to solve x

Answer 10

Thank you ganeshie!