Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (azureilai):

If f(x)=x^5+x^3+x, what is the inverse of f(x)? I am stuck on the fact that there are three x's on the right side and when I try to factor I can't factor anything but one y out. (I'm using x-y substitution method) Any hints would be appreciated thanks.

ganeshie8 (ganeshie8):

may i knw why do you want to find the inverse ?

OpenStudy (azureilai):

It is extra practice I'm doing because I want to review some pre-cal stuff before calculus.

ganeshie8 (ganeshie8):

i don't see any easy way to find the inverse.. could you provide more context of the problem and maybe post the actual complete question if psble

geerky42 (geerky42):

Did you come up this question yourself?

OpenStudy (azureilai):

Ok. The actual question gives f(x), but it asks for f\[f ^{-1}(3)\] and \[f(f ^{-1}(2))\]. No I didn't come up with it myself. It was in my book for the "before calculus" section.

OpenStudy (azureilai):

So far I got \[x=y(y^{4}+y^{2}+1)\] and I don't know where to go from there.

OpenStudy (irishboy123):

solve \(x^5+x^3+x = 3\) and you'll get the inverse \(f^{−1}(3)\)

ganeshie8 (ganeshie8):

actually you don't need to do any work here just notice that \(f\) eats \(f^{-1}\)

ganeshie8 (ganeshie8):

\[\require{cancel}\large{f(f^{-1}(3))\\~\\ \cancel{f}(\cancel{f^{-1}}(3)) \\~\\~\\3}\]

ganeshie8 (ganeshie8):

the inverse function "undoes" whatever the actual function does

OpenStudy (azureilai):

I can see how that would apply to the second question. The answer would come out to two. But for the first question where it only ask for the inverse, should I just graph it and see what it comes out to?

ganeshie8 (ganeshie8):

Ahh no, just use irishboy's hint

OpenStudy (azureilai):

ok thank you.

ganeshie8 (ganeshie8):

solve \(x^5+x^3+x = 3\) and you'll get the inverse \(f^{−1}(3)\) is it hard to guess the \(x\) value that satisfies the above equation ?

OpenStudy (azureilai):

I see it now. wow. Thanks again.

ganeshie8 (ganeshie8):

np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!