If f(x)=x^5+x^3+x, what is the inverse of f(x)? I am stuck on the fact that there are three x's on the right side and when I try to factor I can't factor anything but one y out. (I'm using x-y substitution method) Any hints would be appreciated thanks.
may i knw why do you want to find the inverse ?
It is extra practice I'm doing because I want to review some pre-cal stuff before calculus.
i don't see any easy way to find the inverse.. could you provide more context of the problem and maybe post the actual complete question if psble
Did you come up this question yourself?
Ok. The actual question gives f(x), but it asks for f\[f ^{-1}(3)\] and \[f(f ^{-1}(2))\]. No I didn't come up with it myself. It was in my book for the "before calculus" section.
So far I got \[x=y(y^{4}+y^{2}+1)\] and I don't know where to go from there.
solve \(x^5+x^3+x = 3\) and you'll get the inverse \(f^{−1}(3)\)
actually you don't need to do any work here just notice that \(f\) eats \(f^{-1}\)
\[\require{cancel}\large{f(f^{-1}(3))\\~\\ \cancel{f}(\cancel{f^{-1}}(3)) \\~\\~\\3}\]
the inverse function "undoes" whatever the actual function does
I can see how that would apply to the second question. The answer would come out to two. But for the first question where it only ask for the inverse, should I just graph it and see what it comes out to?
Ahh no, just use irishboy's hint
ok thank you.
solve \(x^5+x^3+x = 3\) and you'll get the inverse \(f^{−1}(3)\) is it hard to guess the \(x\) value that satisfies the above equation ?
I see it now. wow. Thanks again.
np
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