Question

Dont remember how to do this one...

Answer 1

Solve the equation by the square root property.

(x-9)^2=9

Answer 2

@Nnesha

Answer 3

square root property
so you should take square root both sides to cancel out the square

Answer 4

square root and square cancel each other out
bec you can convert square root to 1/2 exponent \[\huge\rm\sqrt{x}=x^\frac{ 1 }{ 2 }\]
so when you take square \[(x^\frac{ 1 }{ 2 })^2\] both 2 cancels out then you have left with just x
so that's why we should take square root to cancel out square
and square to cancel out the square root

Answer 5

Ummm okay?

Answer 6

so take square root both sides what did you get ?

Answer 7

Sorry but I dont understand

Answer 8

thats fine
so what u didn't understand ?

Answer 9

Um basically everything you said :/

Answer 10

otay so
take square root both sides to cancel out the square \[\huge\rm \sqrt{(x-9)^2}=\sqrt{9}\]

Answer 11

Ohhh okay

Answer 12

That turns into-

x-9= +- 3

Answer 13

x=9 +- 3

Answer 14

The solution set is 6 and 12

Answer 15

\[\huge\rm x-9 = \pm 3\]
so x-9 = -3 and x-9 =3

Answer 16

yep

Answer 17

Wow I didnt remember that at all till you showed me with the square root. Lol thank you again

Answer 18

I might be asking for more of your help later. Im on question 4 out of 23 -.-

Answer 19

ohh np
and sure1