Question

Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3x + 3.

Answer 1

A. y = 3 over 2x − 3
B. y = 3 over 2x + 3
C. y = negative 2 over 3x + 23 over 3
D. y = negative 2 over 3x − 23 over 3

Answer 2

@jim_thompson5910 @mathmate

Answer 3

ok so we are going to use point slope form

Answer 4

do you know the point slope formula

Answer 5

@cheetah21

Answer 6

is y2 -y1/x2-x1?

Answer 7

no that is the formula for finding slope the formula for point slope is

\[y -y _{1}=m(x-x _{1})\]

Answer 8

Oh okay my bad so how do we do that ?

Answer 9

well they pretty much give you everything

what is the slope?

Answer 10

*hint
since it is parallel the slope are the same

Answer 11

the slope is 2?

Answer 12

is this how your equation looks
\[y=\frac{ 2 }{ 3 }x+3\]

is so then the slope is 2/3x

Answer 13

yeah that how it looks except the fraction is negative

Answer 14

oh okay sorry so the slope is
-2/3x

Answer 15

its okay(: soo whats next

Answer 16

now you plug in the values
the slope for m
and the point (7,3) for x(1) and y(1)

Answer 17

so y - 3 = m(x-7) ?

Answer 18

yes but plug in the slope for m

Answer 19

Okay i changed the m to -2/3, now what cause im having a little trouble solving it

Answer 20

solve for y

Answer 21

7y times -2/3?

Answer 22

k idk what you did to get that lol

but when you distribute you should get
\[y-3=-\frac{ 2 }{ 3 }x-\frac{ 14 }{ 3 }\]

Answer 23

I got that i just dont know where to go from there

Answer 24

wait it should be \[y-3=-\frac{ 2 }{ 3 }+\frac{ 14 }{ 3 }\]

Answer 25

then combine like terms

Answer 26

y-3=16/3