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OpenStudy (anonymous):

The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two?

OpenStudy (anonymous):

Electric force=\[electric force=\frac{ ke*q1*q2 }{ r^2 }\] Coulomb constant is ke ke is equal to 8.987 x 10^9 Nm^2/C^2 q1 is first charge so it would be 5C q2 is the second charge so it would be 7C r is the distance in meters which is 1.2m

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