Question

please help!!!!!!!!

f(x)=3x-6
g(x)=x-2

find f(g) and domain

Answer 1

Basically you need to put in G(x) into all the x values of the F(x) function.

f(g) = 3(x-2) - 6
f(g) = 3x-6-6
f(g) = 3x-12 --> final answer.

Answer 2

You can think of it like this:
f(x)=3x-6 and rewrite it to f(x)= 3*unit -6
g(x)=x-2 and rewrite it to g(x)= unit-2

find f(g) and domain

f(g)= f(x-2)
now we know f(x) is 3*unit -6 and our unit now is (x-2)

f(g)= 3(x-2) - 6
f(g)= 3x-6-6 Expand brackets
f(g)= 3x-12

Domain can be real numbers since both f(g) and g(x) are functions with real values

Answer 3

@marigirl
@kieran01pd2016 i know it equals 3x-12 but the answers only supplies me with a)3
b)-3
c)1

Answer 4

fg has to be a single number for the answer i just dont know what

Answer 5

`f(g)` makes no sense to be honest

it should be `f(g(x))` or something like `f(g(23))`

Answer 6

its -3

Answer 7

I guess if you did say `f(g)`, it would mean you replace every x in f(x) with g

f(x)=3x-6
f(g)=3g-6

but that's not what they want

Answer 8

scan or link the question, pls :p

Answer 9

@irishboy123 sadly my class supplied this exact question only with nothing else

Answer 10

It's 3 guys thanks .

Answer 11

I think idk just gonna guess thanks

Answer 12

Well, good luck yo!

Answer 13

Let f(x) = 3x - 6 and g(x) = x - 2. Find (f*g) and states its domain?
A. 3; all real numbers except x = 2
B. –3; all real numbers except x = 3
C. 1; all real numbers
D. 3; all real numbers

Answer 14

did you mean (f/g)(x) ?

Answer 15

or f(x)/g(x) ?

Answer 16

It's f times g , it makes no sense to me but it's the question

Answer 17

This is a very awful question. I think they meant to ask f/g because none of the answer choices make sense if it was f*g

Answer 18

\[\Large (f/g)(x) = \frac{f(x)}{g(x)}\]

\[\Large (f/g)(x) = \frac{3x-6}{x-2}\]

\[\Large (f/g)(x) = \frac{3(x-2)}{x-2}\]

\[\Large (f/g)(x) = \frac{3\cancel{(x-2)}}{\cancel{x-2}}\]

\[\Large (f/g)(x) = 3\]

where x cannot equal 2 (to avoid division by zero errors)

Answer 19

yeah ill ask about if it was f/g would the answer be a

Answer 20

IF it was f*g, then you'd have

\[\Large (f*g)(x) = f(x)*g(x)\]

\[\Large (f*g)(x) = (3x-6)*(x-2)\]

\[\Large (f*g)(x) = 3x^2-6x-6x+12\]

\[\Large (f*g)(x) = 3x^2-12x+12\]