Question

How do I solve this?

http://i.imgur.com/QbVYfgf.png

Answer 1

Scale up the number, but first you need to know the mass percent composition of C in \(C_6H_{14}O_3\)

\(\sf mass~percent ~composition~of~C=\dfrac{Molar~Mass~of~C}{Molar~mass~of ~C_6H_[14}O_3}\)

Answer 2

\( \sf mass~percent ~composition~of~C= \dfrac{Molar~Mass~of~C}{Molar~mass~of ~C_6H_{14}O_3} \)

Answer 3

12/134

Answer 4

Then you have a simple ratio: \(\sf \dfrac{Percent ~of~C}{37.2~g}=\dfrac{1}{x~grams~of~C_6H_{14}O_3}\)