Question

Solve log 2x2 + 2 = 6. Round to the nearest thousandth if necessary.

Answer 1

is it \[\huge\rm log 2x^2 +2 =6\] ?

Answer 2

I'm getting \[50\sqrt{2} \] or just about 70.711

Answer 3

is it \[\huge\rm log (2x^2 +2 )=6\] ?
or 2 is base ?

Answer 4

can help :(
???

Answer 5

*cant

Answer 6

its um log 2x^2 + 2 = 6 (log and 2x^2 are seperate)

Answer 7

oh so this is right \[\huge\rm log (2x^2 +2 )=6\]
2 isn't base

Answer 8

alright can you please explain how you got the answer :=)
what was ur first step ? :=)

Answer 9

hmm
\[\huge\rm log_2 (x^2+2)=6\]
\[\huge\rm log (2x^2+2)=6\]
which is ur question ?

Answer 10

it's the second one

Answer 11

I subtract 2 from both sides

log10 (2x^2) + 2 -2 = 6-2

log10 (2x^2)=4

I then used a = logb (b^a)

so... 4= log10 (10^4)

log10 (2x^2) = log10 (10^4)


then all this other stuff/ not sure I want to type it all out lol

Answer 12

@Nnesha