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Chemistry 19 Online
OpenStudy (anonymous):

Anyone that can help real quick? Consider the following reaction: 2 H2S (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2H2 (g) + S 2 (g) Which answer represents the equilibrium constant for this reaction?

OpenStudy (anonymous):

Equilibrium constant is \[K _{c}=\frac{ [D]^d[E]^e }{[A]^a[B]^b }\] where aA+bB >><< dD+eE

OpenStudy (anonymous):

Which answer represents the equilibrium constant for this reaction? The concentration of H subscript two to the exponent 2 multiplied by the concentration of S2 in the numerator all over the concentration of H2S to the exponent 2 in the denominator. The concentration of H subscript two multiplied by the concentration of S2 in the numerator all over the concentration of H subscript two S in the denominator. Two times the concentration of H subscript two multiplied by the concentration of S subscript two in the numerator all over two times the concentration of H subscript two S in the denominator. The concentration of Hsubscript two S to the exponent 2 in the numerator all over the concentration of H subscript two multiplied by the concentration of S subscript two in the denominator.

OpenStudy (anonymous):

@Shalante

OpenStudy (anonymous):

A and B are reactants a and b are constants of the reactants D and E are products d and e are constant of the products. Try it!

OpenStudy (anonymous):

I hate to be too blunt.. but i don't know how to do this very well.. ill give u the medal if you can explain while giving the answer.. please?

OpenStudy (anonymous):

@Shalante

OpenStudy (anonymous):

What is the reactant in this equation? and products?

OpenStudy (anonymous):

really ... really don't know

OpenStudy (anonymous):

reactant >>>>> products <<<<<

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

would it be answer B?

OpenStudy (anonymous):

Reactants are in bottom and products are in top

OpenStudy (anonymous):

ohhhhhh its C?

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

Not telling until you know how to do it.

OpenStudy (anonymous):

Explain your reasoning or are you just guessing over them?

OpenStudy (anonymous):

What is D and E?

OpenStudy (anonymous):

Even though i got the wrong answer ill give u a medal cause I'm in a good mood.

OpenStudy (anonymous):

Oh it was a test or assignment?

OpenStudy (anonymous):

the answer was A

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